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Two-column pier coping · ACI 318-25

A worked example — a two-column pier-coping D-region

A two-column pier coping spans between two columns and carries the girder bearing reactions down to them. Like the single-column case it is a D-region, designed with a strut-and-tie model — here is the same workflow in AStrutTie on the two-column geometry.

Based on the AStrutTie 2020 Technical Book, Example 01 §1.2 (two-column pier), run under ACI 318-25.

Given

  • fck = 24 MPa (concrete)
  • fy = 400 MPa (steel)
  • φ = 0.75 (strength-reduction factor)
  • Coping dimensions, bearing plates & service loads — entered in the template (see the drawing below)
①

The problem

A two-column pier coping carries the girder bearing reactions across to two supporting columns. Its geometry, bearings and loads define the design — typed straight onto the drawing.

Two-column pier-coping geometry and dimensionsTwo-column pier-coping geometry and dimensions
External geometry, bearings and loads of the two-column coping.
②

Build the model — template → strut-and-tie

The pier-coping template builds a strut-and-tie model automatically: struts (compression, dashed), ties (tension, solid), and nodal zones typed CCC / CCT / CTT. It is then refined to follow the load path between the two columns.

Strut-and-tie model of the two-column copingStrut-and-tie model of the two-column coping
The strut-and-tie model on the AStrutTie canvas.
③

Analyze & check — every member, every combination

This coping is statically indeterminate (degree 2), so it is solved by ACore stiffness analysis; every member is then checked against the code — here 49 / 0.

Two-column coping analysis resultsTwo-column coping analysis results
Analysis · Check — indeterminate model solved by stiffness analysis, 49 / 0.
④

Tie check — required reinforcement

ACI 318-25

Required steel As,req is compared with the provided bars (size × count). φ = 0.75, fy = 400 MPa.

As,req = Fu / (φ · fy)
Required reinforcement table for the two-column coping tiesRequired reinforcement table for the two-column coping ties
Tie checks — required vs provided A_s per member.
⑤

Strut check — effective strength & width

ACI 318-25

Effective strength depends on strut type — Boundary (fce = 0.85 fck = 20.4 MPa) or Interior, reinforced (0.637 fck = 15.3 MPa). The required width must fit the available width.

fce = 0.85 · βs · βc · fck
wreq = Fu / (φ · fce · b) ≤ wprov
Strut strength verification of the two-column copingStrut strength verification of the two-column coping
Strut checks — f_ce, required width and safety factor per member.
⑥

Nodal-zone check — by node type

ACI 318-25
fce = 0.85 · βn · βc · fck
wreq = Fu / (φ · fce · b) ≤ wprov
Nodeβnfce (MPa)
CCC1.020.4
CCT0.816.3
CTT0.612.2
Nodal-zone strength verification of the two-column copingNodal-zone strength verification of the two-column coping
Nodal-zone checks — each face against its node type.
⑦

Development length check — anchorage at the node

ACI 318-25 §23.8.2 · §25.4

The tie must be anchored at the node: the available anchorage ℓanc (§23.8.2, extended nodal zone) must reach the required development length ℓd (§25.4). Available = straight length along the tie — no hook-tail credit: ℓdh is measured to the outside of the hook, so the hook's contribution is already in the required length.

Tie anchorage verification of the two-column copingTie anchorage verification of the two-column coping
Development length check — available ℓanc vs required development ℓd.

These are the same checks AStrutTie runs — and Technical Book Example 01 is one of the cases our verification gate holds the engine to, unsafe-side zero. How we verify →

Try it on your own numbers

Open AStrutTie in your browser, sign in with your email and start from the same template. The Free plan needs no installation and no card.